A) \[{{E}_{1}}={{E}_{2}}\]
B) \[{{E}_{1}}=4{{E}_{2}}\]
C) \[{{E}_{1}}=\frac{1}{2}{{E}_{2}}\]
D) \[{{E}_{1}}=2{{E}_{2}}\]
Correct Answer: D
Solution :
\[\because \] \[E=\frac{hc}{\lambda }\] \[\therefore \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{16000}{8000}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{2}{1}\] \[{{E}_{1}}=2{{E}_{2}}\]You need to login to perform this action.
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