A) \[C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}},C{{H}_{3}}C{{H}_{2}}CO{{O}^{-}}\]
B) \[C{{H}_{3}}C{{H}_{2}}COON{{H}_{2}},C{{H}_{3}}C{{H}_{2}}COOH\]
C) \[C{{H}_{3}}C{{H}_{2}}CN,C{{H}_{3}}C{{H}_{2}}COOH\]
D) \[C{{H}_{3}}C{{H}_{2}}CN,C{{H}_{3}}C{{H}_{2}}CO{{O}^{-}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}COON{{H}_{4}}\xrightarrow[-2{{H}_{2}}O]{{{P}_{2}}{{O}_{5}}}C{{H}_{3}}C{{H}_{2}}CN\xrightarrow{{}^{{{H}^{+}}}/{}_{{{H}_{2}}O}}\] \[\underset{\text{Propanoic acid}}{\mathop{C{{H}_{3}}C{{H}_{2}}COOH}}\,\]You need to login to perform this action.
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