A) \[20\,\Omega \]
B) \[2\,\,\Omega \]
C) \[\text{0}.2\,\,\Omega \]
D) \[2\,\,k\Omega \]
Correct Answer: B
Solution :
Let \[{{i}_{a}}\] be the current flowing through ammeter and i the total current. So, a current \[i-{{i}_{a}}\] will flow through shunt resistance. Potential difference across ammeter and shunt resistance is the same, That is \[{{i}_{a}}\times R=(i-{{i}_{a}})\times S\] or \[S=\frac{{{i}_{a}}R}{i-{{i}_{a}}}\] ... (i) Given, \[{{i}_{a}}=100A,\,\,i=750A,\,\,R=13\,\,\Omega \] Hence, \[S=\frac{100\times 13}{750-100}=2\,\,\Omega \]You need to login to perform this action.
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