A) \[{{i}_{2}}>{{i}_{3}}>{{i}_{1}}\]
B) \[{{i}_{2}}>{{i}_{1}}>{{i}_{3}}\]
C) \[{{i}_{1}}>{{i}_{2}}>{{i}_{3}}\]
D) \[{{i}_{1}}>{{i}_{3}}>{{i}_{2}}\]
Correct Answer: B
Solution :
In Circuit (1), on closing the switch, the current in the inductor is zero due to self-induction, i.e.; = 0. In Circuit (2), on closing the switch the current in the inductor is zero due to self-induction. Therefore, \[{{i}_{2}}=i'=\frac{E}{{{R}_{1}}}\] In Circuit (3), on closing the switch, the current the inductor is again zero due to the same reason. Therefore, \[{{i}_{3}}=i'=\frac{E}{{{R}_{1}}+{{R}_{2}}}\] Thus, it is obvious that, \[{{i}_{2}}>{{i}_{3}}>{{i}_{1}}\,\left( =\text{0} \right)\]You need to login to perform this action.
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