NEET Sample Paper NEET Sample Test Paper-70

  • question_answer
    A beam of 35.0 keV electrons strikes a molybdenum, denum target, generating the X-rays. What is the cutoff wavelength?

    A) 35.5 pm                      

    B) 40.0 pm

    C) 15.95 pm                    

    D) 18.2 pm

    Correct Answer: A

    Solution :

    The cut-off wavelength \[{{\lambda }_{\min }}\] corresponds to an electron transferring (approximately) all of its energy to an X-ray photon, thus producing a photon with the greatest possible frequency and least possible wavelength. From relation \[{{\lambda }_{\min }}=\frac{hc}{{{K}_{0}}}=\frac{(4.14\times {{10}^{-15}})(3\times {{10}^{8}})}{35.0\times {{10}^{3}}}\] \[=3.55\times 1{{0}^{-11}}\,\,=\, 35.5\,pm.\]


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