A) \[13.6 \times 1.6 \times \,\,{{10}^{-}}^{19}\,J\]
B) \[3.4 \times 1.6 \times \,\,{{10}^{-}}^{19}\,J\]
C) \[1.51 \times 1.6 \times \,\,{{10}^{-}}^{19}\,J\]
D) 0
Correct Answer: B
Solution :
The electrostatic PE is zero when the electron and proton are far apart from each other. Work done in pulling electron and proton far away from each other \[W={{E}_{f}}-{{E}_{i}}=0-{{E}_{i}}=-\left( \frac{-13.5}{{{n}^{2}}}\,eV \right)\] \[\Rightarrow \,\,\,W=\frac{13.6}{{{\left( 2 \right)}^{2}}}\times 1.6\times {{10}^{-19}}J=3.4\times 1.6\times {{10}^{-19}}\,J\]
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