A) \[\frac{g}{6.4}\]
B) 0.64 g
C) \[\frac{g}{32}\]
D) 0.2 g
Correct Answer: D
Solution :
\[\operatorname{Weight} of the body=64N\] so mass of the body \[\operatorname{m}= 6.4 kg,\,\,{{\mu }_{s}}=0.6,\,\,{{\mu }_{k}}=0.4\] Net acceleration \[=\,\,\frac{Applied\,\,force-Kinetic\,\,friction}{Mass\,\,of\,\,the\,\,body}\] \[=\,\,\frac{{{\mu }_{s}}mg-{{\mu }_{k}}mg}{m}=({{\mu }_{s}}-{{\mu }_{k}})g=(0.6-0.4)g\]\[=\,\,0.2\,\text{g}\]
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