A) \[1.99\times {{10}^{30}}\,kg\]
B) \[7.56\times {{10}^{22}}\,kg\]
C) \[5.98\times {{10}^{24}}\,kg\]
D) \[7.65\times {{10}^{22}}\,kg\]
Correct Answer: D
Solution :
\[{{g}_{m}}=\frac{G{{M}_{m}}}{R_{m}^{2}}\,\,and\,\,{{g}_{m}}=\frac{{{g}_{e}}}{6}=\frac{9.8}{6}m/{{s}^{2}}=1.63m/{{s}^{2}}\]Substituting \[{{R}_{m}}=1.768\times {{10}^{6}}m,\,\,{{g}_{m}}=1.63\,\,m/{{s}^{2}}\] and \[\operatorname{G}=6.67\,\,\times \,\,10{{~}^{-11}}\,N-\,{{m}^{2}}/k{{g}^{2}}\] We get \[{{M}_{m}}=7.65\,\,\times \,\,1{{0}^{22}}kg\]
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