| 1 litre of mixture \[\operatorname{X}+excess AgN{{O}_{3}} \to \,\,Y\]. |
| 1 litre of mixture \[\operatorname{X}+excess BaC{{l}_{2}} \to \,\,Z\]. |
| Number of moles of Y and Z are |
A) 0.01, 0.01
B) 0.02, 0.01
C) 0.01, 0.02
D) 0.02, 0.02
Correct Answer: A
Solution :
\[\underset{0.02\,\,mole}{\mathop{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}S{{O}_{4}} \right]}}\,\,\,Br+AgN{{O}_{3}}\,\,\to \] \[~\underset{0.02\,\,mole\,\,(y)}{\mathop{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}\cdot S{{O}_{4}} \right]}}\,N{{O}_{3}} +AgBr\] \[\underset{0.02\,\,mole}{\mathop{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Br \right]}}\,S{{O}_{4}} +\,\,BaC{{l}_{2}}\,\,\to \] \[\underset{0.02\,\,mole}{\mathop{~\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Br \right]}}\,C{{l}_{2}}+BaS{{O}_{4}}\] On using 1 L solution, we will get 0.01 mole of y and 0.01 mole of z.
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