A) 8.0 cm
B) 10.0 cm
C) Any value less than 12.0 cm
D) 4.0 cm
Correct Answer: B
Solution :
Let the minimum amplitude of SHM is a. Restoring \[F=ka\] Restoring force is balanced by weight mg of block. For mass to execute simple harmonic motion of amplitude a. \[\therefore \,\,\,\,\,\,\,ka=mg\] or \[a=\frac{mg}{k}\] Here, \[\operatorname{m}= 2 kg,\,\,k =200 N/m,\,\,g= 10 m/{{s}^{2}}\] \[\therefore \,\,\,\,a=\frac{2\times 10}{200}=\frac{10}{100}m\] \[=\,\,\,\,\,\frac{10}{100}\times 100\,\,cm=10\,\,cm\] Hence, minimum amplitude of the motion should be 10 cm, so that the mass gets detached from the pan.You need to login to perform this action.
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