A) \[{{10}^{3}}\,g\,\,atom\]
B) \[{{10}^{2}}\,g\,\,atom\]
C) \[{{10}^{4}}\,g\,\,atom\]
D) 10 g atom
Correct Answer: A
Solution :
Weight of Avogadro number (N) of atoms of the element \[= 6.644\,\,\times \,\,1{{0}^{-}}^{23}\times 6.023 \times 1{{0}^{23}}\] \[=\,\,40\,g\] \[40 g = weight of 1\,\,g atom\] \[\therefore \,\,\,40 \times 1{{0}^{3}}g = weight of 1{{0}^{3}}g atom\]
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