A) \[40\,\,k\Omega \]
B) \[4\,\,k\Omega \]
C) \[200\,\,\Omega \]
D) \[400\,\,\Omega \]
Correct Answer: D
Solution :
The term ?LED? is abbreviated as ?Light Emitting Diode?. It is forward-biased p-n junction which emits spontaneous radiation. Current in the \[\operatorname{circuit} =10 mA = 10 \times 1{{0}^{-}}^{3}A\] and voltage in the circuit \[=6-2=4V\] From Ohm?s law. \[\operatorname{V}=IR\] \[\therefore \,\,\,\,\,\,\,R=\frac{V}{I}=\frac{4}{10\times {{10}^{-3}}}=400\,\Omega \]
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