A) \[-2 \times 1{{0}^{-3}}\]
B) \[-1 \times 1{{0}^{-3}}\]
C) \[2 \times 1{{0}^{-3}}\]
D) \[1 \times 1{{0}^{-3}}\]
Correct Answer: D
Solution :
Fractional change in period \[\frac{\Delta T}{T}=\frac{1}{2}\,\alpha \Delta \theta =\frac{1}{2}\times 2\times {{10}^{-6}}\times 10={{10}^{-5}}\] \[%\,Change\,\,=\,\,\frac{\Delta T}{T}\times 100=10{{~}^{-5}}\times 100=1{{0}^{-3}}\,%\]You need to login to perform this action.
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