A) T
B) 9T
C) 27F
D) T/9
Correct Answer: B
Solution :
\[V{{P}^{3}}=constant\,\,=\,\,k\,\,\,\Rightarrow \,\,\,P=\frac{k}{{{V}^{1/3}}}\] Also \[\operatorname{PV}=\mu RT\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\frac{k}{{{V}^{1/3}}}.V=\mu RT\] \[\Rightarrow \,\,\,\,\,\,\,{{V}^{2/3}}=\frac{\mu RT}{k}\] Hence \[{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{2/3}}=\frac{{{T}_{1}}}{{{T}_{2}}}\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\,{{\left( \frac{V}{27V} \right)}^{2/3}}\,=\,\,\frac{T}{{{T}_{2}}}\]You need to login to perform this action.
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