A) \[10{}^\circ C/cm\]
B) \[12{}^\circ C/cm\]
C) \[25{}^\circ C/cm\]
D) \[20{}^\circ C/cm\]
Correct Answer: C
Solution :
\[\frac{\Delta Q}{\Delta t}=\frac{KA\Delta \theta }{\Delta x}\,\,\,\,\,\,\,\Rightarrow \,\,\,\,Thermal\,\,gradient\,\,\frac{\Delta \theta }{\Delta x}\] \[=\,\,\,\,\frac{\left( \Delta Q/\Delta t \right)}{KA}=\frac{10}{0.4}\,\,=\,\,25{}^\circ C/cm\]You need to login to perform this action.
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