NEET Sample Paper NEET Sample Test Paper-71

  • question_answer
    The amplitude and the time period in a SHM is 0.5 cm and 0.4 sec respectively. If the initial  phase is Till radian, then the equation of SHM  will be          

    A) \[\operatorname{y}=0.5 \,sin\,\,5\pi t\]    

    B) \[\operatorname{y}=0.5 \,sin\,\,4\pi t\]

    C) \[\operatorname{y}=0.5 \,sin\,\,2.5\,\pi t\]

    D)   \[\operatorname{y}=0.5 \,\cos \,\,5\pi t\]

    Correct Answer: D

    Solution :

    \[=\,\,a\,\,sin\,\left( \frac{2\pi }{T}t+\phi  \right)\] \[\Rightarrow \,\,\,\,y=0.5\,\,\sin \,\left( \frac{2\pi }{0.4}t+\frac{\pi }{2} \right)\] \[=\,\,\,0.5\,\,\sin \,\left( 5\pi \,t+\frac{\pi }{2} \right)\,\,=\,\,0.5\,\,\cos \,\,5\pi t\,\]


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