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NEET Sample Paper NEET Sample Test Paper-71

  • question_answer
    The capacity and the energy stored in a parallel plate condenser with air between its plates are respectively\[{{\operatorname{C}}_{o}}\,\,and\,\,{{W}_{o}}\]. If the air is replaced by glass \[\left( dielectric constant = 5 \right)\] between the plates, the capacity of the plates and the energy stored in it will respectively be

    A) \[5{{C}_{o}},\,\,5{{W}_{o}}\]

    B) \[5{{C}_{o}},\,\,\frac{{{W}_{o}}}{5}\]

    C) \[\frac{{{C}_{o}}}{5},\,\,5{{W}_{o}}\]                        

    D) \[\frac{{{C}_{o}}}{5},\,\,\frac{{{W}_{o}}}{5}\]

    Correct Answer: B

    Solution :

    When a dielectric K is introduced in a parallel plate condenser its capacity becomes K times. Hence C? \[=\,\,\,5\,{{C}_{0}}.Energy\,\,stored\,\,{{W}_{0}}=\frac{{{q}^{2}}}{2{{C}_{0}}}\] \[\therefore \,\,\,\,\,\,\,\,W'\,\,=\,\,\frac{{{q}^{2}}}{2C'}=\frac{{{q}^{2}}}{2\times 5{{C}_{0}}}\,\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\,\,\,W'=\frac{{{W}_{0}}}{5}\]


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