A) 1.0
B) 2.0
C) 3.0
D) 4.0
Correct Answer: D
Solution :
\[{{K}_{1}}\] for reaction \[2HI\,\,\rightleftharpoons \,\,{{H}_{2}}\,\,+\,\,{{I}_{2}}\] is 0.25 and \[{{K}_{2}}\] for reaction \[{{H}_{2}}+{{I}_{2}}\rightleftharpoons 2HI\] will be \[{{K}_{2}}=\frac{1}{{{K}_{1}}}=\frac{1}{0.25}=4\] Because IInd reaction is the reverse of Ist.You need to login to perform this action.
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