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NEET Sample Paper NEET Sample Test Paper-71

  • question_answer
    Vapour pressure of a solution of 5 g of non- electrolyte in 100 g of water at a particular temperature is\[2985 N/{{m}^{2}}\]. The vapour pressure of pure water is\[3000 N/{{m}^{2}}\]. The molecular weight of the solute is

    A) 60                                

    B) 120

    C) 180                  

    D) 380

    Correct Answer: C

    Solution :

                \[\frac{\,P{}^\circ -{{P}_{S}}}{P{}^\circ }=\frac{\frac{{{W}_{2}}}{{{M}_{2}}}}{\frac{{{W}_{1}}}{{{M}_{1}}}}=\frac{3000-2985}{3000}=\frac{\frac{5}{{{M}_{2}}}}{\frac{100}{18}}\] or  \[{{M}_{1}} = 180\]


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