A) \[{{H}_{2}},\,\,{{O}_{2}}\]
B) \[{{O}_{2}},\,\,{{H}_{2}}\]
C) \[{{O}_{2}},\,\,Na\]
D) \[{{O}_{2}},\,\,S{{O}_{2}}\]
Correct Answer: A
Solution :
At cathode: \[2{{H}^{+}}+2{{e}^{-}}\to {{H}_{2}}\] At anode: \[2O{{H}^{-}}~\to \,\,{{H}_{2}}O\,\,+\,\,\frac{1}{2}\,\,{{O}_{2}}+2e{{~}^{-}}\]
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