A) \[50 : 1\]
B) \[1 : 50\]
C) \[100 : 1\]
D) \[1 : 100\]
Correct Answer: B
Solution :
If a wire of length l is bent in the form of a circle of radius r, then \[2\pi r=1\,\,\Rightarrow \,\,r=\frac{l}{2\pi }\,\] \[r=\frac{l}{2\pi }=\frac{{{\pi }^{2}}}{2\pi }=\frac{\pi }{2}\] Magnetic field due to straight wire \[{{B}_{1}}=\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{2i}{r}=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2\times 2}{1\times {{10}^{-2}}}\] also magnetic field due to circular loop \[{{B}_{2}}=\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{2\pi i}{r}=\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{2\pi \times 2}{\pi /2}\] \[\Rightarrow \,\,\,\,\,\frac{{{B}_{2}}}{{{B}_{1}}}=\frac{1}{50}\]You need to login to perform this action.
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