A) 2 m/sec in original direction
B) 2 m/sec opposite to the original direction
C) 4 m/sec opposite to the original direction
D) 4 m/sec in original direction
Correct Answer: A
Solution :
\[{{\nu }_{1}}=\left( \frac{{{m}_{1}}-{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}} \right){{u}_{1}}+\frac{2{{m}_{2}}{{u}_{2}}}{{{m}_{1}}+{{m}_{2}}}\] Substituting \[{{m}_{1}}=0,\,\,{{\nu }_{1}}=-{{u}_{1}}+2{{u}_{2}}\] \[\Rightarrow \,\,\,\,\,{{\nu }_{1}}= -6 + 2\left( 4 \right) = 2 m/s\] That is, the lighter particle will move in original direction with the speed of 2 m/s.You need to login to perform this action.
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