A) cupellation
B) electrolytic refining
C) zone refining
D) poling
Correct Answer: A
Solution :
Cupellation, Pb present in Ag is removed by cupellation. \[Pb+\frac{1}{2}{{O}_{2}}\,\xrightarrow{{}}PbO\,\,\uparrow \] Because Pb has more affinity for oxygen as compared to Ag.You need to login to perform this action.
You will be redirected in
3 sec