A) 8 V
B) 16 V
C) 10 V
D) not possible to determine unless values of R and C are given
Correct Answer: B
Solution :
Voltage across capacitor lags behind current by\[90{}^\circ \]. The given circuit is a \[\operatorname{C} -R\] series circuit, \[{{V}_{R}}\] is in phase with i while \[{{V}_{C}}\] behind i by\[90{}^\circ \]. Hence, resultant potential is \[E={{E}_{o}}\,sin\,\omega t\]You need to login to perform this action.
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