A) 6
B) 5
C) 4
D) 3
Correct Answer: D
Solution :
\[\overline{\nu }=\frac{1}{\lambda }={{R}_{H}}\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\] \[=\,\,\frac{1}{\lambda }={{R}_{H}}\left[ \frac{1}{3_{{}}^{2}}-\frac{1}{n_{2}^{2}} \right]={{n}_{2}}=3\] for Paschen series.You need to login to perform this action.
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