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NEET Sample Paper NEET Sample Test Paper-73

  • question_answer
    A body is moving from rest under constant acceleration and let \[{{S}_{1}}\] be the displacement in the first \[(p-1)\] sec and \[{{S}_{2}}\] be the displacement in the first p sec. The displacement in \[\left( {{p}^{2}}-p +1 \right)th\] sec will be

    A) \[{{\operatorname{S}}_{1}}+{{S}_{2}}\]                     

    B) \[{{\operatorname{S}}_{1}}{{S}_{2}}\]

    C) \[{{\operatorname{S}}_{1}}-{{S}_{2}}\]                      

    D) \[{{\operatorname{S}}_{1}}/{{S}_{2}}\]

    Correct Answer: A

    Solution :

    From \[\operatorname{S} = ut + \frac{1}{2}a{{t}^{2}}\] \[{{S}_{1}}=\frac{1}{2}a{{(P-1)}^{2}}\,\,and\,\,{{S}_{2}}=\frac{1}{2}a{{P}^{2}}\,\,\,\,\,\,\left[ As\,\,u=0 \right]\] \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\] \[{{S}_{({{p}^{2}}-p+1)th}}\,\,=\,\,\frac{a}{2}\left[ 2({{p}^{2}}-P+1)-1 \right]\] \[=\,\,\frac{a}{2}\left[ 2{{p}^{2}}-2p+1 \right]\] It is clear that \[{{S}_{({{p}^{2}}-p+1)th}}={{S}_{1}}+{{S}_{2}}\]


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