A) \[4\pi T\left( n{{r}^{2}}-{{R}^{2}} \right)\]
B) \[\frac{4}{3}\pi \left( {{r}^{3}}n-{{R}^{2}} \right)\]
C) \[4\pi T\left( {{R}^{2}}-{{n}^{2}} \right)\]
D) \[4\pi T\left( n{{r}^{2}}+{{R}^{2}} \right)\]
Correct Answer: A
Solution :
Energy needed = Increment in surface energy = (surface energy of n small drops) - (surface energy of one big drop) \[=n4\pi {{r}^{2}}T-4\pi {{R}^{2}}T=4\pi T\left( n{{r}^{2}}-{{R}^{2}} \right)\]
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