question_answer

A pendulum clock keeps correct time at\[0{}^\circ C\]. Its mean coefficient of linear expansions is \[\alpha /{}^\circ C\], then the loss in seconds per day by the clock if  the temperature rises by \[t{}^\circ C\] is           

A) \[\frac{\frac{1}{2}\alpha t\times 864000}{1-\frac{\alpha t}{2}}\]  

B) \[\frac{1}{2}\alpha t\times 86400\]

C) \[\frac{\frac{1}{2}\alpha t\times 86400}{{{\left( 1-\frac{\alpha t}{2} \right)}^{2}}}\]        

D) \[\frac{\frac{1}{2}\alpha t\times 86400}{1-\frac{\alpha t}{2}}\]