A) \[{{\operatorname{S}}_{1}}+{{S}_{2}}\]
B) \[{{\operatorname{S}}_{1}}{{S}_{2}}\]
C) \[{{\operatorname{S}}_{1}}-{{S}_{2}}\]
D) \[{{\operatorname{S}}_{1}}/{{S}_{2}}\]
Correct Answer: A
Solution :
From \[\operatorname{S} = ut + \frac{1}{2}a{{t}^{2}}\] \[{{S}_{1}}=\frac{1}{2}a{{(P-1)}^{2}}\,\,and\,\,{{S}_{2}}=\frac{1}{2}a{{P}^{2}}\,\,\,\,\,\,\left[ As\,\,u=0 \right]\] \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\] \[{{S}_{({{p}^{2}}-p+1)th}}\,\,=\,\,\frac{a}{2}\left[ 2({{p}^{2}}-P+1)-1 \right]\] \[=\,\,\frac{a}{2}\left[ 2{{p}^{2}}-2p+1 \right]\] It is clear that \[{{S}_{({{p}^{2}}-p+1)th}}={{S}_{1}}+{{S}_{2}}\]You need to login to perform this action.
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