A) \[N{{H}_{3}} > As{{H}_{3}} > P{{H}_{3}} > Sb{{H}_{3}}\]
B) \[Sb{{H}_{3}} > As{{H}_{3}} > P{{H}_{3}} > N{{H}_{3}}\]
C) \[Sb{{H}_{3}} > N{{H}_{3}} > As{{H}_{3}} > P{{H}_{3}}\]
D) \[N{{H}_{3}} > P{{H}_{3}} > As{{H}_{3}} > Sb{{H}_{3}}\]
Correct Answer: C
Solution :
Boiling points of \[{{\operatorname{SbH}}_{3}}\](254 K), \[N{{N}_{3}}\](238 K), \[As{{H}_{3}}\](211 K) and \[P{{H}_{3}}\](185 K); therefore boiling points are of the order\[{{\operatorname{SbH}}_{3}}>N{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}\].
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