A) \[BeF_{3}^{-}\]
B) \[OH_{3}^{+}\]
C) \[NH_{2}^{{}}\]
D) \[N{{F}_{3}}\]
Correct Answer: A
Solution :
\[Be{{F}^{-}}_{3}\] does not show \[{{\operatorname{sp}}^{3}}-hybridization\] because this compound is not formed.You need to login to perform this action.
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