A) OR
B) NAND
C) AND
D) NOR
Correct Answer: C
Solution :
First two similar gates are NOT gates and the third one is NOR gate. The simple diagram can be shown as The output of gate \[1 =\,\,\overline{A}\] The output of gate \[2\,\,=\,\,\overline{B}\] The output of gate 3 \[Y=\overline{\overline{A}+\overline{B}}\] Use DeMorgan?s theorem \[\overline{\overline{A}+\overline{B}}\,\,=\,\,\overline{\overline{A}}\,.\,\overline{\overline{B}}\] Hence, \[Y=\overline{\overline{A}}\,.\,\overline{\overline{B}}\] \[Y=A\,.\,B\] This is the Boolean expression of AND gate.You need to login to perform this action.
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