A) 10.3 cal
B) 14.3 cal
C) 16.3 cal
D) 18.3 cal
Correct Answer: B
Solution :
As two resistances are in parallel combination So, the effective resistance \[R'=\frac{10\times 10}{10+10}=5\,\Omega \] Heat produced \[=\,\,\frac{{{V}^{2}}}{R'}\times t=\frac{{{1}^{2}}}{5}\times 5\times 60\,J=\frac{60}{4.2}\,\,cal\] \[=\,\,14.3 cal\]You need to login to perform this action.
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