A)
B)
C)
D)
Correct Answer: A
Solution :
\[V=iR\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(V=Potential\,\,difference)\] \[EL=iR~~~~~\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,~~~~\left( V=EL \right)\] \[E=\frac{iR}{L}~=\frac{i\rho }{A}~~~\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,~~~~\left( R=\frac{\rho L}{A} \right)\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,E=\frac{n{{e}^{-}}A\,{{v}_{d}}\rho }{A}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,E=n{{e}^{-}}\,{{v}_{d}}\,\rho \,\,\,or\,\,\,{{v}_{d}}\propto E\]You need to login to perform this action.
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