A) +15 cm
B) +150 cm
C) +250 cm
D) None of these
Correct Answer: A
Solution :
As, magnification \[\left| m \right|=\frac{{{f}_{o}}}{{{f}_{e}}}\left( 1+\frac{{{f}_{e}}}{D} \right)\] So, \[m\propto \frac{1}{{{f}_{e}}}\] \[\therefore \] In order to produce largest magnification the focal length of eye-piece should be small i.e., \[+\,15\,cm\] lens is used.You need to login to perform this action.
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