A) 0
B) 1
C) 3
D) 4
Correct Answer: A
Solution :
In\[{{\left[ Ni{{\left( CN \right)}_{4}} \right]}^{2-}}\], the oxidation state of Ni is +2. \[N{{i}^{2+}}=\left[ Ar \right]3{{d}^{8}}4{{s}^{0}}\] Since, CN is a strong ligand hence it will form low spin complex due to pairing of electrons.You need to login to perform this action.
You will be redirected in
3 sec