A) \[s{{p}^{3}}{{d}^{2}}\]
B) \[{{d}^{2}}s{{p}^{3}}\]
C) \[s{{p}^{3}}{{d}^{3}}\]
D) None of these
Correct Answer: B
Solution :
CN is a strong ligand hence it causes the formation of inner orbital complex due to pairing. Oxidation sate of Fe in \[{{[Fe{{(CN)}_{5}}\,({{H}_{2}}O)]}^{3\,+}}\] is \[\operatorname{x}-5+0=+3\] \[\operatorname{x}=+ 2\] According to VBT hybridisation of \[{{[Fe{{(CN)}_{5}}({{H}_{2}}O)]}^{3\,+}}\] is determined as Vacant orbital electronic configuration of Fe in \[{{\left[ Fe{{(CN)}_{5}}({{H}_{2}}O) \right]}^{3\,+}}\] \[\operatorname{Hybridisation}={{d}^{2}}s{{p}^{3}}\]You need to login to perform this action.
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