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NEET Sample Paper NEET Sample Test Paper-75

  • question_answer
    Two sound waves with wavelength 5 m and 5.5 m respectively are propagating in a gas with velocity 330 m/s. We expect the following number of beats per second.

    A)  1                                

    B)  0

    C)  6

    D)  12

    Correct Answer: C

    Solution :

    As, \[frequency\,\,\text{=}\,\,\frac{velocity}{wavelength}\] Frequency of wave having wavelength 5 m \[{{v}_{1}}=\frac{330}{5}=66\,Hz\] Frequency of wave having wavelength 5.5 m \[{{v}_{2}}\,\,=\,\,\frac{330}{5.5}=60\,Hz\] \[\therefore \] Number of beats per second \[= {{v}_{1}}- {{v}_{2}} = 66 - 60 = 6\]                                 


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