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NEET Sample Paper NEET Sample Test Paper-75

  • question_answer
    The mass number of He is 4 and that of sulphur is 32. The radius of sulphur nucleus is larger than that of helium by the factor of

    A)  2                                

    B)  4                       

    C)  \[\sqrt{8}\]                               

    D)  8

    Correct Answer: A

    Solution :

    As, \[r\propto {{(A)}^{1/3}}\] \[{{A}_{He}}=4,\,\,{{A}_{s}}=32\] \[\therefore \,\,\,\,\,\,\,\,\,\frac{{{r}_{s}}}{{{r}_{He}}}={{\left( \frac{{{A}_{s}}}{{{A}_{He}}} \right)}^{1/3}}={{\left( \frac{32}{4} \right)}^{1/3}}={{\left( 8 \right)}^{1/3}}=2\]


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