A) \[2\times {{10}^{-\,6}}\,M\]
B) \[1\times {{10}^{-\,4}}\,M\]
C) \[1.6\times {{10}^{-\,4}}\,M\]
D) \[4\times {{10}^{-\,6}}\,M\]
Correct Answer: B
Solution :
\[M{{X}_{2}}\,\rightleftharpoons \,\,\underset{(s)}{\mathop{{{M}^{2\,+}}}}\,\,\,+\,\,\underset{(\,\,\,2s)}{\mathop{2{{X}^{-}}}}\,\] \[{{K}_{sp}}=[{{M}^{2+}}]{{[{{X}^{-}}]}^{2}}=(s)\times \,{{(2s)}^{2}}\] \[4\times 1{{0}^{-}}^{12}\,M=4{{s}^{3}}\] \[=1{{0}^{-\,4}}M\]You need to login to perform this action.
You will be redirected in
3 sec