A) \[500\,\mu A\]
B) \[250\,\,\mu A\]
C) \[0.01\,\,\mu A\]
D) \[0.25\,\,\mu A\]
Correct Answer: A
Solution :
Given, \[current gain\,\,B =50\] as \[50\,\,=\,\,\frac{\Delta {{l}_{c}}}{\Delta {{l}_{B}}}\,\,\,\Rightarrow \,\,\,\Delta lc=50\,\,\Delta {{l}_{B}}\] As, input resistance \[=\,\,1k\,\Omega \,\,=\,\,{{10}^{3}}\,\Omega \] \[\operatorname{Input} voltage =0.01V\] \[\therefore \,\,\,\,\,\,\,\Delta {{l}_{B}}=\frac{Input\,\,voltage}{Input\,\,resis\tan ce}=\frac{0.01}{{{10}^{3}}}={{10}^{-5}}\,A\]\[\therefore \,\,\,\,\,\,\,\,\,\,\,\Delta lc=50\times 1{{0}^{-\,5}}=500\,\mu A\]
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