A) \[90\,\]%
B) \[10\,%\]%
C) \[30\,%\]%
D) \[50\,%\]%
Correct Answer: A
Solution :
The efficiency of transformer \[\eta =\frac{Energy\,\,obtained\,\,from\,\,\sec ondary\,\,coil}{Energy\,\,given\,\,to\,\,primary\,\,coil}\] \[=\,\,\,\frac{Output\,\,power}{Input\,\,power}=\frac{{{V}_{S}}{{I}_{S}}}{{{V}_{P}}{{I}_{P}}}\] Given, \[{{V}_{S}}{{I}_{S}} =\,\,100\,W,\,\,{{V}_{P}} =220V,\,\,{{I}_{P}}=0.5 A\] \[\therefore ~\,\,\,\,\,\,\,\eta =\frac{100}{220\times 0.50}\,\,=\, 0.90 = 90\,\]%
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