A) \[{{H}_{2}}S{{O}_{4}}\]
B) \[B{{r}_{2}}/{{H}_{2}}O\]
C) \[HN{{O}_{3}}\]
D) dil. HCL
Correct Answer: B
Solution :
\[Glu\cos e\,\,\xrightarrow[[O]]{B{{r}_{2}}/{{H}_{2}}O}\,\,gluconic\,\,acid\]
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