A) \[{{\operatorname{CO}}_{2}} and N{{O}_{2}}\]
B) \[{{\operatorname{BF}}_{3}}\,\,and N{{N}_{3}}\]
C) \[NO_{3}^{-}\,\,and CC{{l}_{4}}\]
D) \[NO_{{}}^{+}\,\,and Sb{{H}_{5}}\]
Correct Answer: D
Solution :
Species having same total number of valence electrons are isoelectronics with each other. Total valence electrons in \[N{{O}^{+}}=\frac{5+6-1}{2}=10\] Total valence electrons in \[Sb{{H}_{5}}=5+5=10\]
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