NEET Sample Paper NEET Sample Test Paper-75

  • question_answer
    The repeating unit present in asbestos is

    A)  \[{{\left[ S{{i}_{4}}{{O}_{11}} \right]}^{6\,-}}\]                    

    B)  \[{{\left[ Si{{O}_{4}} \right]}^{4\,-}}\]

    C)  \[{{\left[ S{{i}_{2}}{{O}_{7}} \right]}^{2\,-}}\]                      

    D)  \[{{\left[ S{{i}_{3}}{{O}_{9}} \right]}^{3\,-}}\]

    Correct Answer: A

    Solution :

    Molecular formula of asbestos is \[\operatorname{Ca}.M{{g}_{3}}O\left( S{{i}_{4}}{{O}_{11}} \right)\] in which silicate is present as\[{{\left( S{{i}_{4}}{{O}_{11}} \right)}^{4\,-}}\]. Some of \[SiO_{4}^{-}\] tetrahedra share. Three oxygen and other shares two oxygen atom. This is an example of double chain silicates.


You need to login to perform this action.
You will be redirected in 3 sec spinner