A) 8.4 min
B) 6.3 min
C) 4.2 min
D) 12.6 min
Correct Answer: B
Solution :
\[Power =Vi =220V \times 4A=880\,\,J/s\] Heat required to raise temperature of 1 kg of water through \[80{}^\circ C=\left( ms\Delta T \right)\times 4.2\,\,J\] \[=1000\times 1\times 80\times 4.2=336\times 1{{0}^{3}}J\] \[\therefore \,\,\,\,\operatorname{Time}= \frac{336\times 1{{0}^{3}}}{880} =\,\,382\,\,s =6.3\,\,min\]You need to login to perform this action.
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