A) \[2:1\]
B) \[1:1\]
C) \[1:4\]
D) \[1:2\]
Correct Answer: C
Solution :
For 1 st Bohr orbit of hydrogen \[mvr=\frac{h}{2\pi }\,\,\Rightarrow \,\,2\pi r=\frac{h}{mv}\] Now, de-Broglie wavelength of electron having same velocity, \[\lambda =\frac{h}{mv}\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{2\pi r}{\lambda }=1\]You need to login to perform this action.
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