A) 276.7 cal
B) 376.7 cal
C) 298.5 cal
D) 398.5 cal
Correct Answer: A
Solution :
Here initial temperature, \[{{T}_{1}} = 300 K\] Final temperature \[{{\operatorname{T}}_{2}}\, = \,370 K\] If gas is compressed adiabatically, then work done on the gas is \[W=\frac{R}{(1-r)}({{T}_{2}}-{{T}_{1}})\] \[\frac{8.2\times \left( 370-300 \right)}{(1-1.5)}=11.6\times {{10}^{2}}\,J\] \[\operatorname{Heat} produced\,\,H\,\,=\,\frac{W}{J} =\,\,\frac{11.62\times {{10}^{2}}}{4.2}= 276.7 cal\]You need to login to perform this action.
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