A) \[-191 -47J {{K}^{-}}^{1}\,mo{{l}^{-}}^{1}\]
B) \[191.24 J{{K}^{-}}^{1}\]
C) \[83.03 J{{K}^{-}}^{1}\]
D) \[83.03 J{{K}^{-}}^{1}\,mo{{l}^{-}}^{1}\]
Correct Answer: A
Solution :
Given, \[{{V}_{2}}=100 L, \,{{V}_{1}}= 10 L\] \[\Delta S=-\,2.303 nR log\,\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)\] \[=\,\,\,- 2.303\,\,nR\,\,log \left( \frac{100}{10} \right)\] \[=\,\,-2.303 \times 10\,\,\times \, 8.314 J{{K}^{-\,1}}\,mo{{l}^{-\,1}}\] \[=\,\,\,\,-191.47\,J{{K}^{-\,1}}\,mo{{l}^{-\,1}}\]
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