A) 0
B) 4.92
C) 3.87
D) 2.83
Correct Answer: A
Solution :
Let oxidation state of Fe in \[{{\operatorname{K}}_{3}} \left[ Fe{{\left( CN \right)}_{5}}\left( {{H}_{2}}O \right) \right]\] is x \[\left( +1 \right)\times 3+x+5\times \left( -1 \right)+0=0\] \[+3+x\,\,-\,5=0\] \[x=5-3=+\,2\] Magnetic moment of \[F{{e}^{+}}\] can be calculated as as \[\mu =\,\,\sqrt{n(n+2)}\,BM\] where \[n =number of unpaired electrons\] electronic configuration of \[F{{e}^{2+}}\] in \[\left[ Fe{{\left( CN \right)}_{5}}\left( {{H}_{2}}O \right) \right]\] is \[=\,\,\,[Ar]\,3{{d}^{6}}\,4s{}^\circ \,4p{}^\circ \]You need to login to perform this action.
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